Question

how much work is done by an electric motor to pump 50 kg of water to a height of 40 metres. also calculate the power of the motor if it completes this work in 25 seconds.(given: g= 10 ms^-2)​

Answer 1

Answer:

work done=20000 kg m^2 /s^2or j

power=800j/s

Explanation:

w= mgh

=50×40×10

=20000 ans

and power =w/t

= 20000/25

= 800 j/s ans

Answer 2

Explanation:

${ \sf{ \tiny{ \pink{given \: m \: = 50kg , = {10ms}^{2} , \: h =40m }}}} \\ { \sf{ \tiny{ \pink{so \: work \: done = force \times distance = m \times g \times h = 50 \times 10 \times 40 = 20000j}}}} \\ { \sf{ \tiny{ \pink{ \therefore \: work \: done \: by \: the \: motor \: is \: 20000 \: j.}}}} \\ { \sf{ \tiny{ \pink{now \: power \: p = \frac{20000}{25} = 800w }}}} \\ { \sf{ \tiny{ \pink{ \therefore \: the \: power \: of \: the \: motor \: is \: 800 \: w}}}}$