Physics, asked by mfurqaan2018, 8 months ago

how much work is done by an ideal gas in expanding from a volume of 3 liters to a volume of 33 liters against a constant pressure of 2.5 atm ?​

Answers

Answered by zahaansajid
4

Work done = P∆V

= 2.5(33-3) = 2.5 × 30 = 75

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Answered by Ashishkumar098
1

Answer:

Work done by the gas : 75 J

Explanation:

Work done by the ideal gas = P∆V [ where, P = pressure, ∆V = change in volume i.e. ∆V = Final Volume (V2) - Initial Volume (V1) ]

W = P∆V

= 2.5 × ( V2 - V1)

= 2.5 × ( 33 - 2 )

= 2.5 × 30

= 75 J

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