how much work is done by an ideal gas in expanding from a volume of 3 liters to a volume of 33 liters against a constant pressure of 2.5 atm ?
Answers
Answered by
4
Work done = P∆V
= 2.5(33-3) = 2.5 × 30 = 75
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Answered by
1
Answer:
Work done by the gas : 75 J
Explanation:
Work done by the ideal gas = P∆V [ where, P = pressure, ∆V = change in volume i.e. ∆V = Final Volume (V2) - Initial Volume (V1) ]
W = P∆V
= 2.5 × ( V2 - V1)
= 2.5 × ( 33 - 2 )
= 2.5 × 30
= 75 J
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