How much work is done by the gravitational force of earth acting on a satellite
moving around it in a circular path?
explain
Answers
Explanation:
No work is , done by the gravitational force of the earth acting on a satellite moving around it in a circular part because the gravity is always pointing towards the the centre of the earth which provides the centripetal force required for circular motion and the satellite is going tangentially ,the angle between is 90 degrees
Answer:
The work done by the gravitational force of the earth on a satellite moving around it in a circular path is zero.
Explanation:
The gravitational force of the earth is always acting towards its center. This gravitational force provides the necessary centripetal force for the satellite to move in a circular path. Since the satellite is executing a circular path its direction at a particular point will be tangential to that point. So the centripetal force and the direction of the satellite will always be perpendicular to each other. ie; θ = 90°
We have work done, W = F s Cosθ
Since θ = 90°, Cosθ = Cos90° = 0
∴W = F s × 0
W = 0