Question

how much work is done if 240 L of argon gas irreversibly double in volume against 1 bar of pressure ?​

Answer 1

Answer:pressure volume work" which measures work done by gases when they compress or expand due to pressure. in equation form work = pressure x change in volume. in this situation work is expressed in l x atm (atmosphere). first we calculate the change in volume by subtracting final volume by initial volume. in this case the volume doubled so it is 2v-v which equals v (or 240l). next we convert bar to atm. 1 bar is 100 kilopascale and 101.325 kilo pascals is 1 atmosphere, so in general 1 bar is usually considered to be 1 atm. if we want to be very precise we would divide 100kilopasczle by 101kilopascalw per bar to get .987 atm. in this example we will use 1 so work = 1 atm x 240l = 240 atm x l