Chemistry, asked by person33, 10 months ago

How much work is done if 240 litres of argon gas irreversibly. Double in volume against 1 bar of pressure

Answers

Answered by sharmaayush0459
2

pressure volume work" which measures work done by gases when they compress or expand due to pressure. in equation form work = pressure x change in volume. in this situation work is expressed in l x atm (atmosphere). first we calculate the change in volume by subtracting final volume by initial volume. in this case the volume doubled so it is 2v-v which equals v (or 240l). next we convert bar to atm. 1 bar is 100 kilopascale and 101.325 kilo pascals is 1 atmosphere, so in general 1 bar is usually considered to be 1 atm. if we want to be very precise we would divide 100kilopasczle by 101kilopascalw per bar to get .987 atm. in this example we will use 1 so work = 1 atm x 240l = 240 atm x l

Answered by soniatiwari214
2

Answer:

240 J

Explanation:

  • When gases contract or expand (change in volume) as a result of pressure, work is created. This can be expressed mathematically as follows:
  • W = P V, where W is the work performed by the gas, P denotes pressure, and V denotes volume change.
  • Traditionally, adding work to the system is considered negative. However, when the system produces the work, it is productive.
  • We first determine the volume change by deducting the final volume from the initial volume. In this instance, the volume has doubled, therefore 2v-v equals v. (or 240l). Next, we turn a bar into an ATM. Since 1 bar is equal to 100 kilopascals and 1 atmosphere is equal to 101.325 kilopascals, 1 bar is frequently compared to 1 ATM. To get.987 ATM, we could divide 100 kilopascals by 101 kilopascals per bar if we wanted to be extremely precise. In this example, we'll utilize 1 So work, which is equal to 1 ATM multiplied by 240 l.

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