Question

how much work is done in bringing a charge of 2.5×10^-6 from one point to another if the potential difference between the two points is 4v​

Answer 1

Explanation:

v=w/q

4=w/2.5×10^-6

w=4×2.5×10^-6

w=10×10^-6

w=10^-5J

Answer 2

Therefore the workdone on the charge is 10^-5 Joule.

Given : a charge of magnitude 2.5 × 10^-6 C is being brought from one point to another by applying potential difference between two points is 4 volts.

To find : The work done on the charge bringing from one point to another.

solution : we know, work done on the charge is given by, W = q × ∆P

where q is the charge and ∆P is the potential difference between the points.

⇒W = 2.5 × 10^-6 × 4

= 10^-5 J

Therefore the workdone on the charge is 10^-5 Joule.