Question

How much work is done in moving a 500 new coulomb charge between two points on an equipotential surface?

Answer 1

Hey user!

Here's the answer you are looking for

Work done is moving a charged particle in an Electric field = ∆V × q

where ∆V is the difference between the potential at the final and initial points.

∆V =V(final) – V(initial)

and q is the charge of the particle.

Here, since the charge is moved in equipotential surface, ∆V = 0

[as V(final) = V(initial)]

Therefore, W = 0×q = 0


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Answer 2

Answer:

W = del V × q

since, del V = V final - V initial and V initial = V final

and therfore del V = 0

So, W = 0 × q = 0.

(a) zero