Question

How much work is done in moving a charge of 2 coulombs from a point at 118 volts to a point at 128 volts ?





Solution. We know that :



Here,
Volts =128-118
=10 volts
work done, W= ? And, charge moved,Q= 2 coulombs

Putting these values in the above formula, we get:

W = 10*2
work done, W= 20 joules
​

Answer 1

Answer:

20 J

Explanation:

We know, potential difference = work done/ charge

p.d. = 128-118=10 V

charge = 2C

work done = 10 V X 2C = 20 J

Answer 2

Answer:

What you wanna to show ?

If you know answer as well than you wasting someone's time?