Question

how much work is done in moving a charge of 2C from a point of 118v to a point of 128v?​

Answer 1

Explanation:

Hey mate!

Here's your answer!!

Charge = 2C

Potential difference = 128 - 118 = 10V

We know,

V = J/C

(V = volts, J = work done, C = charge)

=> 10 = J/2

=> J = 10 × 2 = 20J

hope \: it \: helps \: you.

#BE BRAINLY

✌ ✌ ✌

Answer 2

Answer:

20J

Explanation:

W = Q×∆V

W = 2 × (128-118)

hence...work = 20J