Question

How much work is done in moving a charge of 2C from a point a point at 118V to a point at 128V​

Answer 1

Answer:

Work = q ∆ V

= 2 × ( 128 - 118 )

= 20 Joules

Answer 2

Given ,

• The magnitude is charge is 2 c
• The potential at A and B are 118 v and 128 v

As we know that , the potential difference is given by

$\boxed{ \sf{ V_{b} - V_{a} = \frac{ W_{ab}}{q} }}$

Thus ,

128 - 118 = W/2

10 = W/2

W = 20 joule

$\sf \therefore \underline{The \: work \: done \: is \: 20 \: J}$