how much work is done in moving a charge of 2C, from a point at 120V to a point at 140V ?
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Dev001
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Hey mate!
Here's your answer!!
Charge = 2C
Potential difference = 128 - 118 = 10V
We know,
V = J/C
(V = volts, J = work done, C = charge)
=> 10 = J/2
=> J = 10 × 2 = 20J
Explanation:
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