Question

How much work is done in moving a charge of 2c from a point of 118v to a point 128v​

Answer 1

Answer:

20 J.

Explanation:

Here is your answer......

By using the formula ,

W= (V2 - V1) ×q

W= (128 -118) × 2

W= 20 V C ====> (or) 20J.

Hope this helps you a little!!!!!

Answer 2

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Work needed = 20J

$\red{\mid{\underline{\overline{\textbf{explanation}}}\mid}}$

Work is said to be done when a force is applied on a body and the body undergoes displacement. Work done or needed is measured in Joules.

In field of electricity, the work done in moving the charges is defined as the product of potential difference between the points and charge Transfered. It is defined by the expression :

$\bigstar \: \orange{\mid{\underline{\overline{\textbf{w = v ×q }}}\mid}}$

In this equation :

• w = work done
• v = potential difference
• q = Charge transfered.

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In this question we have been given the intensity of two points and the charge which is transfered from one point to another , the work done in moving the charge is not known we have to calculate it.

In this question :-

• Work done = W = ?
• Charge transfered = q = 2C
• Potential difference = 128V - 118V = 10V

Now after inputting the known values in the expression we get :

$\mapsto \: w = v \times q \\ \\ \mapsto w = 10 \times 2 \\ \\ \mapsto \: w = 20joule \: or \: volts$

Therefore the work needed in moving 2C charge from 118V to 128V is 20Joules.

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BY SCIVIBHANSHU

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