Question

How much work is done in moving a charge of 2c from a point at 118v to a point at 128v?

Answer 1

Hey mate!

Here's your answer!!

Charge = 2C

Potential difference = 128 - 118 = 10V

We know,

V = J/C
(V = volts, J = work done, C = charge)

=> 10 = J/2

=> J = 10 × 2 = 20J

$hope \: it \: helps \: you.$
#BE BRAINLY

✌ ✌ ✌

Answer 2

Given :

Charge (Q) = 2 C

To Find :

Work done in moving the charge

Solution :

Work done in moving the charge = Potential Difference × Charge

Here, Charge = 2 C

Potential Difference (V) = 128 - 118 = 10 V

∴ Work done in moving the charge = 10 × 2

                                                          = 20 J

Hence, the work done in moving the charge from a point at 118 V to a point at 128 V is 20 J.