Question

How much work is done in moving a charge of 2C from a point of 118V to a point of 128V?

Answer 1

✴Question

How much work is done in moving a charge of 2C from a point of 118V to a point of 128V?

________________________________

✴Answer:-

→Given:-

• Tolat Charge=2C
• Point a = 118V
• point b = 128V

→Concept:-

• Simple Work Done problem.

→To Find:-

• Work Done.

→Formula:-

• Work done = Total Charge × Potential Difference.

→Calculation:-

Potential Difference(V)=Point(a)-Point(b)

V = 118-128

V =10 volts

We Know,

Work done = Total Charge × Potential Difference

Putting the values in the above formula,we get:

W = 10 × 2

Thus,Work Done,W=20 joules

________________________________

✴Final Answer:-

Work done= 20 joules.

________________________________

✴More To Know:-

• The work done by a force can be defined as the product of the displacement of an object and the component of the applied force which is in the direction of the object's displacement.

• Electric potential at a point in an electric field, is defined as the amount of work done in order to move a unit positive charge from infinity to that point along any path, against the electrostatic forces,with acceleration zero.

• The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.

_______________________________