Question

how much work is done in moving a charge of 300C across two points having a potential difference 0.1V​

Answer 1

Answer:

Solution: Given:

Potential difference (V)= 15 V

Charge (Q)= 3C

We know that

The potential difference(p.d) between two point in an electric circuit is defined as the amount of work done in moving a unit charge from one point to the other point.

Potential difference (V) = work done (W)/Charge (Q)

V= W/Q

Putting the values in the above formula we get:

15 V=W/3 C

W= 15 V x 3 C W= 45 J

Hence, the work done in moving the charge is 45 J.

Answer 2

Q=300C

V=0.1V

W=?

V=W/Q

W=VQ

=0.1*300

=30J