Question

how much work is done in moving a charge of 5 columb between two points in a circuit having a potential difference of 10 volt?​

Answer 1

Hi !

we know Voltage = Work/Charge.

So , 10= W/5

50 J = Work

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Answer 2

Answer: 50J

Explanation:

In this case, charge of circuit (q) = 5 coloumb

potential difference(Vb-Va) = 10 volt

Let work done = w

we know that Vb - Va = w/q

10 = w/5

w = 10 × 5 = 50 Joule

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