Question

How much work is done in moving a charge of 6C from a point at 210V to a point at 220V

Answer 1

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Electrostatics.

Now basically if we see here, the work done by a charge is always given as,

W = V*Q

but if we see here , there is movement if charge with a potential difference, so we can modify the given formula as,

=> dw = dv*Q

where, dw is the net work done by the body and the dV is the potential difference, so we get as,

=> dW = (220-210)*6

=> dW = (10)*6

⭐=> dW = 60 eV

Answer 2

QuEstion:

How much work is done in moving a charge of 6 C from a point at 210 V to a point at 220 V .

SoluTion:

given electric potential of two points is 210 V and 220 V

so,

potential difference b/w the points(V) = (220 - 210 ) V

$\boxed{ V = 10\: V}$

given charge

$\boxed { Q = 6\:C}$

$\boxed{work\:done\:(W) = V * Q}$

so,

W = 10 * 6 J

W = 60 J .