Question

how much work is done in moving a charge of two columns from a point at 118 volts to a point at 128 volts​

Answer 1

work W= V*Q [ volt into coulomb]

for 118 volt

W = V*Q %D

= 118 * 2

=236 joule

for 128

W = V*Q

= 128 * 2

= 256 joule

work done for 118v to 128v is = 256 - =

236

= 20 joule

Answer 2

Correct Question:

How much work is done in moving a charge of 2 Coulombs from a point at 118 volts to a point at 128 volts?

Required Solution:

Given:

• Initial potential ($\sf {V_A}$) = 118 V
• Final potential ($\sf {V_B}$) = 128 V
• Charge moving (Q) = 2 C

To calculate:

• Work done (W)

Calculation:

We know that,

• V = $\sf {\dfrac {W}{Q} }$

Where,

• V = potential difference
• W = work done
• Q = charge moved

Firstly we have to calculate potential difference (V),we know that:

Potential difference between two points:

• V = $\sf {V_B}$ - $\sf {V_A}$

→ V = 128 - 118

→ V = 10 volts

Now,

• V = $\sf {\dfrac {W}{Q} }$

→ 10 = $\sf {\dfrac {W}{2} }$

→ W = 10 × 2

→ W = 20 J

Therefore, work done is 20 joules.

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Extra!

• Work done in a moving a unit charge from one point to another point is called potential difference.

• Formula : V = W/Q

• SI unit of potential difference is Volt.

• Potential difference is measured by voltmeter.

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