how much work is done in moving charge of 2 coulombs from a point at 118 volts to a point at 128 volts
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The work done is simply charge multiplied by the change in potential.
So it is 2*(128-118) = 20. (sry but i am not sure about the units).
So it is 2*(128-118) = 20. (sry but i am not sure about the units).
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Your question
how much work is done in moving charge of 2 coulombs from a point at 118 volts to a point at 128 volts ?
Too Easy
Your answer
Here ,
Given in the question →
- Charge = 2 C , which has to move in electric field from a point 'A'(118) to point 'B' (128) (say)
- So , Potential difference = 128 - 118 = 10 V
- To Calculate Work done (W) = ?
We use the Formula ,
Work done = Total charge x potential difference
- W = Q ( total ) x V
Here ,
- Q = Total charge = Given = 2 C
And ,
- V = Potential difference = 10 V
So the word done in moving the charge from A to B will be ,
- W = 2 x 10
- W = 20 joules
Work done = 20 joules.
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