Question

How much work is done on a 5 kg block if it is to be moved on a ramp 30 above
the horizontal and height of 1 meter? What are the values of work done by each
force?

Answer 1

Answer

Correct option is

D

50 J

From FBD,

F=mgsinθ+f

or F=mg

x

h

+f as(sinθ=

x

h

)

or Fx=mgh+fx

or W

F

=mgh+W

f

as work done = force × distance.

150=5×10×2+W

f

or W

f

=150−100=50J

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Answer 2

Concept:

The product of an object's displacement and the component of the applied force that is directed in the direction of the object's displacement is known as the work done by a force.

Given:

The mass of the block is 5 kg. It is moved on a ramp 30° above the horizontal and at a height of 1 meter.

Find:

The work done on the block and the work done by each force.

Solution:

The mass of the block, m = 5kg

The angle between the ramp and the horizontal, θ = 30°

The height at which the block is moving from the ground, h = 1m

The work done on the block by the gravity is:

W = -mgh

W = -(5)(10)(1)

W = - 50J

The work done by a normal force is zero.

The work done by the force f = mgcos(θ) is:

W = mgh(cos(θ))

$W=(5)(10)(1)(\frac{\sqrt{3} }{2})\\W=25\sqrt{3} J$

The work done by the force f = mg(sin(θ))

W = mgh(sin(θ))

$W=(5)(10)(1)(\frac{1}{2})\\W=25J$

The work done on the block is -50J.

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