Question

How much work is done to displace horizontally a body 40m by a force of 200N, whose angle with the horizontal is 30°?​

Answer 1

Explanation:

$workdone \: = force \times distance \\ = 200 \cos(30) \times 40 \\ = 173.2 \times 40 \\ 6928j$

Answer 2

Concept:

• The work done
• Resolution of vectors
• Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement.
• It is frequently described in its most basic form as the result of force and displacement.

Given:

• Distance s = 40 m
• Force F = 200 N
• The angle between the force and the horizontal θ = 30°

Find:

• The work done to displace the body

Solution:

We know that work is the dot product of force and displacement.

W = F.s

W = F*s cos θ

W = 200* 40 cos 30°

W = 6928 J

The work done is 6928 J.

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