Question

How much work is done to move a charge of 8 C from a point of potential 30 V to 10 V? (With full process)

Answer 1

Answer:

When charges move in an electric field, something has to do work to get the charge to move. To move q, we apply a force to just barely overcome the repulsive force from Q. Let's work it out: The amount of work done is force times distance, W = F ⋅ d W = F \cdot d W=F⋅dW, equals, F, dot, d .

Answer 2

We know that potential difference = Work done/Charge moved.

In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.

Thus, the potential difference = v2-V1 = 230-240 = 10 V

Therefore, Work done = Potential difference * Charge moved.

That is, 10 * 5 = 50 Joules.

Hence, the work done in moving a charge of 5 coulombs from a point at 230 volts to another point at 240 volts is 50 J.