How much work is done to stretch a spring by 15cm if the spring constant k has the value of 800N/m?
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Hey mate
Long enough to make such an impression Hope this helps
Long enough to make such an impression Hope this helps
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0
Answer:
9Joule
Explanation:
Given,
Extension of the spring, X=15cm
Spring constant, K=800N/m
we know,
Elastic potential energy=1/2KX^2
Therefore, E = 1/2*800*0.15^2
= 400*0.0225
= 9J
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