how much work is nedded to be done on a ball of mass 50g to give it a momentum of 500gcm/s??
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Kinetic energy (K) = 1/2 mv²
p = mv
K = 1/2 m (p/m)²
K = 1/2 p²/m
p = √(2mK)
p = 500 g cm /s = 500/100000 = 5× 10⁻⁵ kg m /s
m = 50 g = 0.05 kg
K = ?
5 × 10⁻⁵ = √(2 × 0.05 × K)
⇒ 5 × 10⁻⁵ = √(0.1K)
⇒ (5 ×10⁻⁵)² = 0.1 K
⇒ 0.1K = 25 × 10⁻¹⁰
⇒ K = 25 × 10⁻⁹ Joules Ans.
Kinetic energy (K) = 1/2 mv²
p = mv
K = 1/2 m (p/m)²
K = 1/2 p²/m
p = √(2mK)
p = 500 g cm /s = 500/100000 = 5× 10⁻⁵ kg m /s
m = 50 g = 0.05 kg
K = ?
5 × 10⁻⁵ = √(2 × 0.05 × K)
⇒ 5 × 10⁻⁵ = √(0.1K)
⇒ (5 ×10⁻⁵)² = 0.1 K
⇒ 0.1K = 25 × 10⁻¹⁰
⇒ K = 25 × 10⁻⁹ Joules Ans.
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