Physics, asked by mirelham2003, 9 months ago

How much work is needed to be done to increase the velocity of an object of mass 2 kg from 3 m/s to 6 m/s?

Answers

Answered by Anonymous
5

Mass of object = 2kg (m)

Initial velocity = 3m/s (u)

Final velocity = 6m/s (v)

By Work Energy Theorem

\large\green{\boxed{W= \triangle KE}}

Where

  • W is work done
  • KE is change in Kinetic Energy.

\implies W = \triangle KE

\implies W = \dfrac{1}{2}mv^{2}-\dfrac{1}{2}mu^{2}

\implies W=\dfrac{1}{2}m(v^{2}-u^{2})

\implies W = \dfrac{1}{2}\times2[(6m/s) ^{2}-(3m/s) ^{2}]

\implies W = \dfrac{1}{\cancel{2}} ×\cancel{2}(36m^{2} s^{-2}-9m^{2}s^{-2})

{\underline{\boxed{.°. W = 25J}}}

Therefore the work done is 25J.

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