English, asked by SAMPATHMAHESH4985, 11 hours ago

how much work is needed to push a 1250 kg car 11.5m up a 13.5 degree inclined

Answers

Answered by rajap84

1

Answer:

(a) No friction.

Work Done = Force x Displacement = mgsin13.5 x 11.5 = 33.557 kJ

(b) Coefficient of friction = 0.09

Work Done = Force x Displacement = (mgsin13.5 + 0.09mgcos13.5) x 11.5 = 46 kJ

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