Question

how much work is required to form a babble of 2cm radius from the soap solution having surface tension 0.07N/m​

Answer 1

★ Applying Work Done Formula :

• ⟹ W = T . 2 x SA

• ⟹ W = T × 2 × 4πr²

• ⟹ W = 0.07 × 2 × 4 × 3.14 × 0.02 × 0.02

• ⟹ W = 7.04 × 10 -⁴ Joules

★ Therefore :

• ⟹ Work Done Required to form a babble of 2cm radius from the soap solution having surface tension 0.07N/m is 7.04 × 10-⁴ J

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