Question

How much work is required to form a bubble of Area 50 cm² from the soap solution having S.T. 0.07 N/m.​

Answer 1

Answer:

Given ,please mark me as the brainliest hope this helps u

surface tension = 0.07 N/m

radius = 2 cm = 0.02 m

surface tension formula shown in above image

surfaces tension = F/d

0.07 = F / 0.02

F = 0.07 0.02

F = 0.0014 N

To find Work. work formula shown in above image

w = F * d

F = 0.0014 N

d = 2 cm = 0.02m

w = 0.0014 × 0.02

w = 2.8 × 10 ^ - 5 Nm

Hope I am answer for your question

Answer 2

Step-by-step explanation:

r = 2 cm = 2×10

−2

m, T= 0.07 N/m

Initial surface area of soap bubble = 0

Final surface area of soap bubble = 2×4πr

2

∴ Increase in surface area = 2×4πr

2

The work done = surface tension × increase in surface area

=T×2×4πr

2

The work done = 0.07×8×3.142×(2x10

−2

)

2

=7.038×10

−4

J.