Question

How much work is required to move a 75.0 kg wooden crate to a distance of 10.0 m in the hallway if a force of 35.0 N is applied 30 degrees with the horizontal ? with explanation plss​

Answer 1

Answer:

• 175√3 Joules is the required answer.

Explanation:

Given:-

• Mass ,m = 75 Kg
• Displacemet ,s = 10 m
• Force ,F = 35 N
• ∅ = 30°

To Find:-

• Work Done , W

Solution:-

we have to calculate the work done to move 75 Kg wooden crate .

When a force acting on body produce some displacemet in the body. Then we said that the work is done by body.

• W = Fs Cos∅

Where,

• W denote Work Done
• F denote Force
• Ø denote angle

Substitute the value we get

→ W = 35 × 10 × Cos30°

Cos30° = √3/2

→ W = 350 × √3/2

→ W = 175√3 J

• Hence, the work required to move the crate is 175√3 Joules.

Answer 2

Required answer -

Let's understand the question 1st -

☯ How much work is required to move a 75.0 kg wooden crate to a distance of 10.0 m in the hallway ,if a force of 35.0 N is applied 30 degrees with the horizontal ?

Given that -

☯ Mass of wooden crate = 75 kg.

☯ Displacement / Distance = 10 m.

☯ Force = 35N

☯ θ = 30°

To find -

☯ Work doned.

Solution -

☯ 175√3 J is work done.

Using concept -

☯ Formula to find work done.

Using formula -

☯ W = Fs Cosθ

We also write these as -

☯ Work done as W

☯ Force as F

☯ Mass as m

☯ Displacement as d

☯ Angel as θ

Full Solution -

✴ W = Fs Cosθ

✴ W = 35(10)Cos30°

✴ W = 350Cos30°

✴ W = 350 × √3/2

✴ W = 175√3

• Henceforth, work done is 175√3 J.

Additional information -

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Maxwell \: is \: unit \: of \: magnetic \: flux}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: magnetic \: flux \: is \: Weber}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: surface \: tension \: is \: \dfrac{N}{m}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: mechanical \: power \: is \: Watt}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto 1 \: horsepower \: = \: approx \: 746 \: watts}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Momentum \: is \: measured \: as \: the \: product \: of \: Mass \: and \: velocity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto \pi \: 'pi' \: is \: calculated \: by \: Aryabhatta}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto One \: J \: = \: 0.24 \: cal}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Number \: of \: SI \: units \: are \: 7}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Ampere \: is \: the \: unit \: of \: current \: electricity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: Young's \: modulus \: of \: elasticity \: is \: Newton/m^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: pressure \: is \: Pascal}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Curie \: is \: the \: unit \: of \: radio \: activity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Decibel \: is \: the \: unit \: of \: intensity \: of \: sound}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: electric \: charge \: is \: coulomb}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: resistance \: is \: ohm}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: acceleration \: is \: ms^{-2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Kinetic \: energy \: is \: given \: by \: \dfrac{1}{2}mv^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Value \: of \: G \: is \: 6.673 \times 10^{-11}Nm^{2}kg{-3}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Dimensional \: formula \: for \: universal \: gravitational \: constant \: is \: M^{-1} L^{3} T^{-2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto The \: unit \: of \: force \: constant \: k \: of \: a \: spring \: is \: \dfrac{N}{m}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Sir \: Cavendish \: was \: the \: first \: to \: gave \: value \: of \: G \: experimentally}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto The \: Young's \: modulus \: for \: perfect \: rigid \: body \: is \: infinite}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Density \: is \: the \: ratio \: of \: \dfrac{Volume}{Mass}}}}$