Question

How much work is to be done to move a charge of
10 C between two points having potential difference
20 V?​

Answer 1

It’s 20X10 = 200 j
*explanation*
H=qv
Q=10c
V=20v
Therefore 10*20= 200 j

Answer 2

Answer:

Find work done =W

Given,

Moving charge =10C=(Q)

Two points having a potential difference of

=20V

h=QV

==10×20

=200J