Question

How much work must be done to pull apart the electron and the proton that make up the hydrogen atom if the atom is initially in the state with n=2

Answer 1

• Given : n = 2

• tart from each other .

• therefore the final potential energy will be 0.

• the work doneE

     W= Final potential energy - initial potential energy

W= 0- initial potential energy (Ei)

W = - Ei

• the initial potential energy of the atom is given by Ei= - 13.6 eV/ n^2

Therefore W

                W= 13.6 eV/n^2

•

Answer 2

Answer:

        The electrosatic P.E. is zero when the electron and proton are far apart from each other. Work done in pulling electron and proton far away from each other is

W=Ef−Ei=0−Ei=−(−13.6/n^2eV)

⇒W=13.6×1.6×10^−19J//(2)^2=3.4×1.6×10^−19J