How much work must be done to stop a 1150-kg car traveling at 145 km/h ?
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Answered by
0
Answer:
By work energy theorem:-
=>W = ∆KE
=>W = 1/2mv^2
=>W = 1/2 x 1150 x (105 x 1000/3600)^2
=>W = 489149.31 J
Answered by
0
Answer:
Work done = ΔKE
W = 1/2mv²
⇒ W = 1/2 (1000) * (100 * 5/18)² = 385802 N
Explanation:
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