Question

how much work should be done on a bicycle of mass 20kg to increase its speed from 2m/s to 5m/s

Answer 1

formula 1/2 m (v×v -u×u)
1/2×20 (5×5 - 2×2)
if we cancel 1/2 ×20 =10 and 25 -4= 21
10×21 210joule

Answer 2

Solutions:

We know that whenever work is done, an equal amount of energy is used up. So, the work done in this case will be equal to the change in kinetic energy of bicycle when its speed changes from 2 m/s to 5 m/s.

(a) In the first case;

Mass of bicycle, m = 20 kg

And, speed of bicycle, v = 2 m/s

So, kinetic energy, Ek = 1/2mv^2

=> 1/2 × 20 × (2)^2

=> 10 × 4

=> 40 J

(b) In the second case;

Mass of bicycle, m = 20 kg

And, speed of bicycle, v = 5 m/s

So, kinetic energy, Ek = 1/2mv^2

=> 1/2 × 20 × (5)^2

=> 10 × 25

=> 250 J

Now, Work done = Change in kinetic energy.

=> 250 - 40

=> 210 J

Thus, the work done is 210 J.