how much work should be done on a bycycle of mass 20 kg to increase its speed from 2ms_1 to 5ms_1
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Answer:
formula 1/2 m(v×v-u×u
1/2×20 (5×5_2×2)
if we cancel 1/20=10 and 25-4=21
10×21 210 is answer
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