how much work should be done on a object of 120kg to increase its speed from 25m/s to 45m/s
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work done is = change in kE
=> 1/2mv²
=> 1/2 m(vf - vi )
=> 1/2m × 20²
=> 1/2× 1200× 400
=> 240000 j
hope it help you !!!
thanks !!!
=> 1/2mv²
=> 1/2 m(vf - vi )
=> 1/2m × 20²
=> 1/2× 1200× 400
=> 240000 j
hope it help you !!!
thanks !!!
sahebrav:
:)
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