Question

How much work should be done on an object of 120 kg to increase its speed from 25
m/s to 40 m/s
(I WILL GIVE BRAINLIEST TO THE ONE WHO ASNWERS!)

Answer 1

heyy here is ur ans..

kinetic energy = 1/2 mv2
k.e.1 = 1/2 × 120 ×( 25 )^2
= 60 × 625 = 37500 j

k.e.2 = 1/2mv^2
= 1/2 ×120 ×( 40 )^2
=60 × 1600 = 96000

work done = k.e2 - k.e1
= 96000 - 37500
= 58500 j

hope it helps u..if it did plzz mark me brainliest...thanks...!!!!