How much work will be done in bringing a charge of 5.0 milicolombs from infinity to a point P at which the potential is 12V?
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Answered by
1
W = V×q
W = 12× 5×0^-3
W = 6×10^-2 Joule...
W = 12× 5×0^-3
W = 6×10^-2 Joule...
Answered by
1
Here,
V = 12V
Q = 5/1000C
V = W/Q
12 = W / 5/1000
12 × 200 = W
W = 6000J
• Your answer is 6kJ.
I hope this answer helped you.
V = 12V
Q = 5/1000C
V = W/Q
12 = W / 5/1000
12 × 200 = W
W = 6000J
• Your answer is 6kJ.
I hope this answer helped you.
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