Question

How much work will done in
increasing velocity from 20m/s.
to 40m/s of a motor cas of
mass 500 kg???​

Answer 1

work done in 40m/s =

=1/2mv^2

= 1/2×500 ×40×40

=400000joule

word done in 20 m/s = 1/2mv^2

= 1/2×500×20×20

= 100000joule.

so,

required work done = 400000j-100000j

= 300000joule.

$<marquee> I hope it will help you$