Question

How much work will it take to bring a charge equal to Q = 300 uC to a charge equal to Q = 20 0 uC at a distance of 1.50 m? How much work will be done when it is at a distance of 0.50 m?​

Answer 1

Answer:

Explanation:

W=ΔU=Kq−Q(10.5−11.5)=K×3×20×10−12[2−23]  

⇒K×3×20×10−12×43=K×80×10−12

=0.72J