Question

how much would a 70 kg man weigh on the moon if acceleration due to gravity is one / six th of earth

Answer 1

Answer:

We should know that weight = mass * gravity.

That is weight equals mass times gravity.

Gravity is a force of attraction between any two bodies in the universe. It is directly proportional to product of their masses and inversely proportional to the square of the distance between them.

Gravity is generally measured in terms of acceleration due to gravity, denoted as g. For Earth it is, 9.8 m/s². And for moon, it is about 1.62 m/s².

On Earth, your weight is 70 kg = W

W = mass x 9.8

70 = mass x 9.8

Your mass is 70/ 9.8

i.e approximately 7.14

Weight at the Moon, W' = 7.14 x 1.62

Hence, your weight on the surface of the moon is just 11.56 kg.

Explanation:

PLS MARK AS BRAINLEIST

Answer 2

$\LARGE\underline{\sf{\red{Solution!!}}}$

αnswєríng thє sєcσnd quєstíσn fírst, mαss ís índєpєndєnt σf thє sчstєm ! α 70-kg mαn hαs α mαss σf 70kg σn αnч plαnєt σr sαtєllítє fσr thαt mαttєr ! whαt chαngєs wíth єαch plαnєt/sαtєllítє ís thє αppαrєnt wєíght σr fσrcє єхєrtєd вч thαt mαss σn thє grσund.

$\longrightarrow$$\sf {W = mg}$

where

$\longrightarrow$$\sf {W : weight~ in~ Newton (N)}$

$\longrightarrow$$\sf {m : Mass ~of ~the ~object ~in ~kilogram (kg)}$

g: αccєlєrαtíσn єхpєríєncєd вч єvєrч σвjєct αrє tσ íts sчstєm’s grαvítч (fσr єαrth, g(є) = 9.81 m/s2 αnd fσr mσσn, g(m) = 1.635 m/s2)

Now to the first question:

чєs, thєrє wσuld вє α díffєrєncє ín thє wєíghts σf thє mαn σn єαrth αnd σn thє mσσn.

• Weight on earth would be, W(e) = m × g(e)

$\longrightarrow$$\sf {W(e) = 70 × 9.81 = 672.7 N}$

• Weight on the moon would be, W(m) = m x g(m)

$\longrightarrow$$\sf {W(m) = 70 × 1.635 = 114.4 N}$

síncє α wєíghíng scαlє ís єssєntíαllч α mєαsurєmєnt σf thє grαvítαtíσnαl pull σn α вσdч, thє αstrσnαut wσuld sєєmínglч wєígh 1/6th σf hís wєíght σn єαrth !

whαt chαngєs ís nσt thє mαss, вut thє grαvítαtíσnαl pull !