Question

How much would it cost to paint the walls of a room
10 m long, 8 m wide and 4 m high, if painting 1 m²
costs 6.50?​

Answer 1

Answer:

936 rs.

Step-by-step explanation:

The wall must be the shape of CUBOID

Hence,

CSA of cuboid = 2h(l+b)

= 2 × 4 × ( 10+8 )

= 2 × 4 × 18

= 144 sq.m.

Hence, 1 sq.m. costs 6.50 rs

144 sq.m. will cost=144 × 6.50

= 936 Rs.

Hope you have understood

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Answer 2

Before, finding the answer. Let's find out we can find the answer.

• In this question, we are asked to find the cost of painting the walls of a room.
• So, to find that, we must find the Lateral Surface Area of the Cuboid. To find the Lateral Surface Area, we must use the formula of :

$\boxed{\sf Lateral \: Surface \: Area \: of \:Cuboid = 2 h (l+ b)}$

• After finding the Lateral Surface Area, we must multiply the cost of painting with the Lateral Surface Area.

_______________________________

Given :

• Length = 10 m
• Breadth = 8 m
• Height = 4 m
• Cost for Painting = Rs. 6.50

To find :

• cost to paint

Solution :

Lateral Surface Area  = 2 h (l+ b)

                                    = 2 × 4 × (10 + 8)

                                    = 2 × 4 × (18)

                                    = 2 × 72

                                    = 144 cm²

Cost for Painting = Cost of Painting × Lateral Surface Area

                            = 6.50 × 144

                            = 936

Therefore, the Cost of Painting the walls of the room is Rs. 936.