how much x^2- 2xy +3yz less than 2x^2-3y^2+xy
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Step-by-step explanation:
2x² - 3y² + xy - ( x² - 2xy + 3yz )
= 2x² - 3y² + xy - x² + 2xy - 3yz ( ∵ - × + = - ; - × - = + )
= ( 2x² - x² ) - 3y² + ( xy + 2xy ) - 3yz ( ∵liketerms )
= x² - 3y² + 3xy - 3yz is the answer.
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