Question

how much x²+y²+2² be increased to get -2x²+3y²-7z² ?​

Answer 1

Answer:

Let in

Step-by-step explanation:

Let increasing no. be k

(x^2+y^2+2^2)+k = (-2x^2+3y^2-7z^2)

k = (-2x^2+3y^2-7z^2)-(x^2+y^2+2^2)

k = -2x^2+3y^2-7z^2-x^2-y^2-2^2

k = -2x^2-x^2+3y^2-y^2-7z^2-4

k = -3x^2+2y^2-7z^2-4