Computer Science, asked by abhijeetlagad063, 1 year ago

how much year later a same calendar can repeat

Answers

Answered by rommieroy

after 4 years.
plss mark it as brainliest.

Anonymous: but how?

rommieroy: i don't know but it's true

Anonymous: you mean you can't explain!!

rommieroy: ya

abhijeetlagad063: but it is not true

abhijeetlagad063: correct answer is 11

Answered by Anonymous

for calculating day of weak
a=[14-month/12]
y=year+4800-a
m=month+12a-3
Julian calender=(day+[153m+2/5]+365y
+(y/4)-(y/100)+(y/400)32045mod7
and in Julian calender leap year is a year which :- year mod 4=0
hope it's helpfull to you!!!

Anonymous: Leap years are not every four years.

They are every four years unless the year is divisible by 100; except if it is divisible by 400 ehen it is a leap year.

mnraza94: For example take 2007 is a year .

mnraza94: count all the years odd days from 2007 to 2020 when u get 7 0r 14 that means . after completion of 7 or 14 next year would be same as the supposed year (eg: 2007).

mnraza94: 2007 has 1 odd day 2008 has 2 odd days 2009 has 1 odd days

mnraza94: 2010 has 1 odd day 2011 has 1 odd day 2012 has 2 odd days 2013 has 1 odd day 2014 has 1 odd day 2015 has 1 odd day 2016 has 2 odd days 2017 has 1 odd day 2018 has 1 odd day 2019 has 1 odd day 2020 has 2 odd day..

mnraza94: Now count all odd days you will reach exact 14 at 2017 that's it .Next year is your expected answer..

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