Question

how much zn required to produce 224 ml of h2 at stp on treatment with dilute h2so4

Answer 1

Ok, haven’t done this since school so bear with me.

22.4L of gas is exactly one mole of any gas at STP. 224.0 ml is 0.224L or one hundredth of a mole of gas at STP.

Zn(s) + H2SO4(aq) ---> ZnSO4(aq) + H2(g) So one mole of Zn(s) produces one mole of H2(g). So one hundredth of a mole of Zn will produce one hundredth of a mole of H2(g). One mole of Zn is 65.38 g so you need one hundredth of a mole of Zn or 0.6538g.

Answer 2

This should act to give 224 ml of hydrogen and perhydrol is actually required to produce sufficient oxygen level in Zn.