Question

How much ZnCI can be produced from the reaction of 2.0 mol of Zn and 3.0 mole of HCI? Which is the limiting reagent? How much of the excess reagent reacts?

Answer 1

Answer:

Zn

Explanation:

Zn+2HCl→ZnCl2+H2

1 mole of Zn reacts with 2 moles of HCl.

2.5 moles of Zn will react with 2×2.5=5.0 moles of HCl.

However 6.0 moles of HCl are present.

Thus, HCl is the excess reactant and Zn is the limiting reactant.