how multiplicative inverse of -5+4 iota
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To find the multiplicative inverse of -5+4 î, the following procedure must be adopted:
Lets suppose that Z = -5+4 î
Then, Inverse of Z = Z⁻¹ = 1/Z
1
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
-5+4 î
1 -5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ X ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
-5+4 î -5 - 4 î
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
(-5+4 î ) (-5 - 4 î )
-5- 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
(-5)² - (4)². (î)²
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ ( î² = -1 )
25 - 16 (-1)
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
25 + 16
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
41
= - (5/41) - (4/41) î
This is the required answer.
Hope it will help u..
Lets suppose that Z = -5+4 î
Then, Inverse of Z = Z⁻¹ = 1/Z
1
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
-5+4 î
1 -5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ X ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
-5+4 î -5 - 4 î
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
(-5+4 î ) (-5 - 4 î )
-5- 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
(-5)² - (4)². (î)²
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ ( î² = -1 )
25 - 16 (-1)
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
25 + 16
-5 - 4 î
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
41
= - (5/41) - (4/41) î
This is the required answer.
Hope it will help u..
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