Question

How n+1/4n+1=1/4+3/4(4n+1) fast anyone plzzz

Answer 1

Solve for n:
n + n/4 + 1 = 1/4 + (3 (4 n + 1))/4
Put each term in n + n/4 + 1 over the common denominator 4: n + n/4 + 1 = (4 n)/4 + n/4 + 4/4:
(4 n)/4 + n/4 + 4/4 = 1/4 + (3 (4 n + 1))/4
(4 n)/4 + n/4 + 4/4 = (4 n + n + 4)/4:
(4 n + n + 4)/4 = 1/4 + (3 (4 n + 1))/4
4 n + n = 5 n:
(5 n + 4)/4 = 1/4 + (3 (4 n + 1))/4
1/4 + (3 (4 n + 1))/4 = (3 (4 n + 1) + 1)/4:
(5 n + 4)/4 = (3 (4 n + 1) + 1)/4
3 (4 n + 1) = 12 n + 3:
(5 n + 4)/4 = (12 n + 3 + 1)/4
Add like terms. 1 + 3 = 4:
(5 n + 4)/4 = (12 n + 4)/4
Multiply both sides by 4:
5 n + 4 = 12 n + 4
Subtract 12 n from both sides:

(5 n - 12 n) + 4 = (12 n - 12 n) + 4
5 n - 12 n = -7 n:
-7 n + 4 = (12 n - 12 n) + 4
12 n - 12 n = 0:
4 - 7 n = 4
Subtract 4 from both sides:
(4 - 4) - 7 n = 4 - 4
4 - 4 = 0:
-7 n = 4 - 4
4 - 4 = 0:
-7 n = 0
Divide both sides of -7 n = 0 by -7:
(-7 n)/(-7) = 0/(-7)
(-7)/(-7) = 1:
n = 0/(-7)
0/(-7) = 0:
Answer: |
| n = 0

Answer 2

x6y6-9x3y3+8(solve the math)