Question

How
Number of gram equivalents of CaCl, produced when 148 g of Ca(OH), is completely
neutralized by HCl solution is
B) 2
D) 4
A) 1
C) 3

Answer 1

As in a chemical reaction , no of equivalents of product and reactant are equal by the Law of Chemical Equivalence, so
No of equivalents of Ca(OH)2 = No of equivalents of CaCl2 produced
So ,
Moles * n-factor [Ca(OH)2] = Moles * n-factor [CaCl2]
So , (148/74)*2 = equivalents of CaCl2 formed
So, No of equivalents of CaCl2 = 4
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