Question

how R = 4H cot theta please explain easily​

Answer 1

We know that, R = (u^2* sin2θ)/ g

Considering max range occurs at an angle of 45deg

R=(u^2*sin90)/9=(u^2)/g....(I)

We also know that, Height attained by a projectile=(Velocity along Y-axis)^2/2g

H= ((u^2)*(sin45))^2)/2g =((u^2)*(1/root2)^2)/2g=u^2/4g....(II)

Compare statements I and II, we get

R=4H ....Hence Proved

Answer 2

Answer:

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